Question

Can you solve this .......................

Answer 1

$\huge\bf\underline{Factorize:}$

$9 {a}^{2} + 30a + 25$

$\huge\bf\underline{Solution:}$

$9 {a}^{2} + 30a + 25 \\ = 9 {a}^{2} + 15a + 15a + 25 \\ = 3a(3a + 5) + 5(3a + 5) \\ = (3a + 5)(3a + 5) \\ ={(3a+5)}^{2}$

Answer 2

$\underline{\mathbf{\huge{Question}}}$

9a²+30a+25

$\underline{\mathbf{\huge{Answer}}}$

9a²+30a+25

=9a²+15a+15a+25

=3a(3a+5)+5(3a+5)

=(3a+5)(3a+5)

=(3a+5)²

$\underline{\mathbf{\huge{Explanation}}}$

By Using Middle Term Spilliting.

In this Divide Middle Term (30) Such that On Adding It Become 30 and On Multiplying it become Product of 1st term (9) and last term(25)

First Step=Multiply First and Last Term

9×25=225

Second Step=Find Factor of 225

225=3×3×5×5

Third Step =Divide Middle Term (30) such that on adding it become 30 and on multiplying it become product of first and last term .

15,15

15+15=30

15×15=225

Fourth Step=9a²+15a+15a+25

Common Between Each Two Terms

9a²+15a

Common=3a

3a(3a+5)

15a+25

common=5

5(3a+5)

Fifth Step=Write each Common Term together

(3a+5) (3a+5)

As we know a×a=a²

(3a+5)²

$\boxed{\mathbf{\huge{Answer={(3a+5)}^{2}}}}$