Math, asked by govindk6440, 1 year ago

Can you solve this ap series

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Reetkaur111: Here is the answer to your question.

In an A.P.,

We have S n = n 2 p

⇒ 2a + ( n – 1 )d = 2np ... (1)

Also, S m = m 2 p

⇒ 2a + ( m – 1) d = 2mp ... (2)

(1) – (2)

2a + ( n – 1 )d – (2a + ( m – 1) d) = 2np – 2mp

⇒ nd – d – md + d = 2p ( n – m)

⇒ (n – m) d = 2p ( n – m)

⇒ d = 2p

Put value of d in equation (1):

2a + ( n – 1 ) 2p = 2np

⇒ a + ( n –1 )p = 2np

⇒ a = np – ( n – 1 ) p

= np – np + p

⇒ a = p

Now s p

= p 2( p)

= p 3

Thus , S p = p 3

Answers

Answered by Arpitsahay18

sorry no i can not

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Answered by bharat9291

here is your solution

Attachments:

govindk6440: Pls prove that sp=p square

bharat9291: bro i think question is wrong

bharat9291: please check if i have committed any mistake

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