can you solve this equation
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{(x+5)*1 + (x-3)*1} / (x-3)*(x+5) =1/3
(x+5 + x-3 ) / x^2 -3x +5x -15 = 1/3
( 2x +2) / x^2 + 2x - 15 = 1 /3
3*(2x +2) = x^2 +2x -15
6x + 6 = x^2 +2x - 15
x^2 +2x -15 -6x -6 =0
x ^2 -4x -21 =0
x^2 +3 x -7x -21 =0
x (x+3) -7 ( x+3) =0
x +3 =0 and x -7 =0
x = -3 and x = 7.
hope it helps u.mark brainliest
(x+5 + x-3 ) / x^2 -3x +5x -15 = 1/3
( 2x +2) / x^2 + 2x - 15 = 1 /3
3*(2x +2) = x^2 +2x -15
6x + 6 = x^2 +2x - 15
x^2 +2x -15 -6x -6 =0
x ^2 -4x -21 =0
x^2 +3 x -7x -21 =0
x (x+3) -7 ( x+3) =0
x +3 =0 and x -7 =0
x = -3 and x = 7.
hope it helps u.mark brainliest
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