Question

can you solve this for me ​

Answer 1

Given :-

Two sides of each triangle is given in the above question,

(i) 38°, 102°

(ii) 116°, 30°

(iii) 40°, 80°

To Find :-

The third angle in each of the triangle given.

Analysis :-

Since only two angles of a triangle are given, we have to find the third angle.

Sum up the first two angles and subtract them from the total sum of a triangle.

Solution :-

(i) 38°, 102°

Total degree of a triangle - (Angle 1 + Angle 2)

We know that,

Total degree of a triangle = 180°

Substituting their values,

$\sf 180-(38+102)$

$\sf 180-140$

$\sf =40^{o}$

Therefore, the third angle is 40°.

(ii) 116°, 30°

Total degree of a triangle - (Angle 1 + Angle 2)

We know that,

Total degree of a triangle = 180°

Substituting their values,

$\sf 180-(116+30)$

$\sf 180-146$

$\sf =34^{o}$

Therefore, the third angle is 34°.

(iii) 40°, 80°

Total degree of a triangle - (Angle 1 + Angle 2)

We know that,

Total degree of a triangle = 180°

Substituting their values,

$\sf 180-(40+80)$

$\sf 180-120$

$\sf =60^{o}$

Therefore, the third angle is 60°.

Answer 2

Answer:-

• Total degree of triangle= 180°
• To find 3 rd angle:-
• $\rm\purple{ \: 180 - (adding \: given \: angles)}$

so,

$\sf \: i)38 ,\: 102$

$38 + 102 = 140$

$180 - 140 = 40$

$\sf\implies\blue{ \: i)40}$

$\sf \: ii)116, \: 30$

$\sf \: 116 + 30 = 146$

$\sf \: 180 - 146 = 34$

$\sf\implies\red{ \: ii)34}$

$\sf \: iii)40 ,\: 80$

$\sf \: 40 + 80 = 120$

$\sf \:180 - 120 = 60$

$\sf\implies\green{ \: iii) 60}$