can you solve this guys please step by step solutions neeeded
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Qno.24
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YOUR BOOK HAS A MISPRINT BECAUSE THE SUM OF THE DIGITS OF THE NUMBER CAN'T BE 18 SINCE IT CAN ONLY HAPPEN IF THE NUMBER IS 99.
SO IN PLACE OF 18 IT SHOULD BE 8 & IN PLACE OF 8 IT SHOULD BE 18.
LET the Ten's digit be x and Unit's digit be y
And Original Number = 10x + y
According to Question,
x + y = 8 ----------- (i)
10x + y + 18 = 10y + x ------------ (ii)
Solving (ii)
10x + y + 18 = 10y + x
10x - x + y - 10y = -18
9x - 9y = -18
x - y = -2 ------- (iii)
ADDING (i) & (iii)
x + y = 8
x - y = -2
_________
2x = 6
x = 3
Substituting x in eq (i)
3 + y = 8
y = 5
ORIGINAL NUMBER = 10x + y
=> 35
>>>>>>>>>>>>>>>>>>>>>>>>>>>
SO IN PLACE OF 18 IT SHOULD BE 8 & IN PLACE OF 8 IT SHOULD BE 18.
LET the Ten's digit be x and Unit's digit be y
And Original Number = 10x + y
According to Question,
x + y = 8 ----------- (i)
10x + y + 18 = 10y + x ------------ (ii)
Solving (ii)
10x + y + 18 = 10y + x
10x - x + y - 10y = -18
9x - 9y = -18
x - y = -2 ------- (iii)
ADDING (i) & (iii)
x + y = 8
x - y = -2
_________
2x = 6
x = 3
Substituting x in eq (i)
3 + y = 8
y = 5
ORIGINAL NUMBER = 10x + y
=> 35
>>>>>>>>>>>>>>>>>>>>>>>>>>>
shuvam2:
okkk
Answered by
0
THE NUMBER CAN'T BE 18 SINCE IT CAN ONLY HAPPEN IF THE NUMBER IS 99.
SO IN PLACE OF 18 IT SHOULD BE 8 & IN PLACE OF 8 IT SHOULD BE 18.
LET the Ten's digit be x and Unit's digit be y
And Original Number = 10x + y
According to Question,
x + y = 8 ----------- (i)
10x + y + 18 = 10y + x ------------ (ii)
Solving (ii)
10x + y + 18 = 10y + x
10x - x + y - 10y = -18
9x - 9y = -18
x - y = -2 ------- (iii)
ADDING (i) & (iii)
x + y = 8
x - y = -2
_________
2x = 6
x = 3
Substituting x in eq (i)
3 + y = 8
y = 5
ORIGINAL NUMBER = 10x + y
=> 35
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