Question

CAN YOU SOLVE THIS HARD QUESTION​

Answer 1

Brainlist pls

Step-by-step explanation:

$\sqrt[3]{ \sqrt{ {y}^{6} } } \\ = > \sqrt[3]{ \sqrt{ {y}^{(3)}(2) } } \\ = > square \: and \: square \\ \: root \: gets \: cancelled \\ = > \sqrt[3]{ {y}^{3} } \\ = > cube \: and \: cube \: root \: gets \\ \: cancelled$

$= > = y$

where y is a positive real number