Question

can you solve this maths question

Answer 1

$\frac{p}{q} = {( \frac{3}{2} )}^{ - 2} + {( \frac{6}{5} )}^{0} \\ \\ \frac{p}{q} = {( \frac{2}{3} )}^{2} + {( \frac{6}{5} )}^{0} \\ \\ \frac{p}{q} = \frac{4}{9} + 1 \\ \\ \frac{p}{q} = \frac{4 + 9}{9} \\ \\ \frac{p}{q} = \frac{13}{9} \:$


${( \frac{p}{q} )}^{ - 2} = {( \frac{p}{9} )}^{ - 2} = \frac{81}{169}$