can you solve this one
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(sin^2B+ cos^2B )^2-2sin^2xcos^2B
use a^2 +b^2=(a+b)^2-2ab
formula
Answered by
1
Step-by-step explanation:
sin⁴α+2sin²cos²α+cos⁴α=1
LHS
sin⁴α+2sin²α cos²α+cos⁴α
=(sin²α)²+2sin²α cos²α+(cos²α)²
=(sin²α+cos²α)²
=1²
=1
RHS
PROVED
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