Question

can you solve this one?

Answer 1

Answer:

Since x+iy=cosh(u+iv)=cos(iu−v)

=cosiucosv+siniusinv

=coshucosv+isinhusinv

∴ equating real and imaginary parts, we get

x=coshucosv and y=sinhusinv

i.e.,

cosv

x

=coshu and

sinv

v

=sinhu

Squaring and subtracting , we get

cos

2

v

x

2

−

sin

2

v

y

2

=cosh

2

u−sinh

2

u=1

Step-by-step explanation:

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