can you solve this problem
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Given that 1/3rd of a number exceeds1/7 by 16.
Let the number be x.
1/3x = 1/7x + 16
1/3x - 1/7x = 16
(7x - 3x)/7 * 3 = 16
4x/21 = 16
4x = 16 * 21
4x = 336
x = 84
Therefore the number = 84.
Verification:
1/3 * 84 = 1/7 * 84 + 16
28 = 12 + 16
28 = 28.
Hope this helps!
Let the number be x.
1/3x = 1/7x + 16
1/3x - 1/7x = 16
(7x - 3x)/7 * 3 = 16
4x/21 = 16
4x = 16 * 21
4x = 336
x = 84
Therefore the number = 84.
Verification:
1/3 * 84 = 1/7 * 84 + 16
28 = 12 + 16
28 = 28.
Hope this helps!
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