Question

Can you solve this problem?

5f5d99569c21081a67ac120a2a77b7cd.pdf

Answer 1

Given problem:-

$\sf \longmapsto\dfrac{y-4}{4}+\dfrac{y-3}{5}=\dfrac{5y-4}{8}$

Solution:-

$\sf \longmapsto\dfrac{y-4}{4}+\dfrac{y-3}{5}=\dfrac{5y-4}{8}$

Taking LCM in denominators of LHS:

$\sf \longmapsto\dfrac{5(y-4)+4(y-3)}{20}=\dfrac{5y-4}{8}$

$\sf \longmapsto\dfrac{5y-20+4y-12}{20}=\dfrac{5y-4}{8}$

Now solving numerator of LHS:

$\sf \longmapsto\dfrac{9y-32}{20}=\dfrac{5y-4}{8}$

Now cross multiplication:

$\sf \longmapsto8(9y-32)=20(5y-4)$

Now solving it:

$\sf \longmapsto72y-256=100y-80$

$\sf \longmapsto-256+80=100y-72y$

$\sf \longmapsto -176=28y$

Divide by 28 from Both LHS and RHS:

$\sf \longmapsto \dfrac{-176}{28}=\dfrac{28y}{28}$

$\boxed{\sf \longmapsto -\dfrac{44}{7}=y}$

This is the required answer.★