can you solve this problem
Answers
Answer:
jdndjdjsjsoiwjehejeueieiwiqjbsbsndjwiiejehrjrhjfirowoejjddhjdjdjdjdjdjdj
Step-by-step explanation:
bxnsjoaowjdheheiwoquehfhnfnjdow
jfjxjdjdjeiiwoeoeifufh
Solution :-
→ x = 2^(1/3) + 2^(-1/3)
cube both sides,
→ x³ = [2^(1/3) + 2^(-1/3)]³
using (a + b)³ = a³ + b³ + 3ab(a + b)
→ x³ = {2^(1/3)}³ + {2^(-1/3)}³ + 3 * 2^(1/3) * (2^(-1/3) * (2^(1/3) + 2^(-1/3))
→ x³ = 2 + 1/2 + 3x
→ x³ = 5/2 + 3x
→ x³ = (5 + 6x)/2
→ 2x³ = 5 + 6x
→ 2x³ - 6x = 5 (Proved).
Learn more :-
Let a, b and c be non-zero real numbers satisfying (a³)/(b³ + c³) + (b³)/(c³ + a³) + (c³)/(a³ + b³)
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if a²+ab+b²=25
b²+bc+c²=49
c²+ca+a²=64
Then, find the value of
(a+b+c)² - 100 = __
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