Math, asked by rohithjatoth1729, 4 days ago

can you solve this problem​

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Answers

Answered by Badboy330
147

\rm\bf\dag\large\underline{Soluation: }

\rm\rightarrow\huge\int \frac{1  +x + \:  \sqrt{x \:  (1+ x)}  }{ \sqrt{x} +  \sqrt{1 + x}  }  \: dx

\rm \rightarrow\huge\int \frac{  \sqrt{1 + x}  \: + \:  \sqrt{  1+ x \:  }  +  \sqrt{x}  }{  \sqrt{1 + x} \:  + \sqrt{x}    }  \: dx

\rm \rightarrow\huge \int \:  \sqrt{1 + x}  \:  \:  \:  \:  \: dx

 \rm \rightarrow\huge\frac{(x + 1) ^{ \frac{3}{2} } } { \:  \frac{3}{2} }  + c

  \rm \rightarrow\huge\frac{2}{3}(1 + x)^{ \frac{3}{2} }  \:  + c

 \rm\bf Your \: answer \:  is, \\  \rm  \frac{2}{3} (1 + x) ^{ \frac{3}{2} }   \: + c

Answered by anuragkumar8432rupdi
0

Answer:

\rm\bf\dag\large\underline{Soluation: }†

Soluation:

\rm\rightarrow\huge\int \frac{1 +x + \: \sqrt{x \: (1+ x)} }{ \sqrt{x} + \sqrt{1 + x} } \: dx→∫

x

+

1+x

1+x+

x(1+x)

dx

\rm \rightarrow\huge\int \frac{ \sqrt{1 + x} \: + \: \sqrt{ 1+ x \: } + \sqrt{x} }{ \sqrt{1 + x} \: + \sqrt{x} } \: dx→∫

1+x

+

x

1+x

+

1+x

+

x

dx

\rm \rightarrow\huge \int \: \sqrt{1 + x} \: \: \: \: \: dx→∫

1+x

dx

\rm \rightarrow\huge\frac{(x + 1) ^{ \frac{3}{2} } } { \: \frac{3}{2} } + c→

2

3

(x+1)

2

3

+c

\rm \rightarrow\huge\frac{2}{3}(1 + x)^{ \frac{3}{2} } \: + c→

3

2

(1+x)

2

3

+c

\begin{gathered} \rm\bf Your \: answer \: is, \\ \rm \frac{2}{3} (1 + x) ^{ \frac{3}{2} } \: + c\end{gathered}

Youransweris,

3

2

(1+x)

2

3

+c

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