Question

can you solve this question

Answer 1

Heya !!

Well it's very interesting question !!

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▶ square × square × square = 27
=> (square)³ = 27
=> square = 3√27
=> square = 3

▶ square × triangle × triangle × triangle = 24
=> 3 × (triangle)³ = 24
=> (triangle)³ = 24/3
=> (triangle)³ = 8
=> triangle = 3√8
=> triangle = 2

▶ square × triangle × circle × circle = 96
=> 3 × 2 × (circle)² = 96
=> (circle)² = 96/6
=> (circle)² = 36
=> circle = √16
=> circle = 4

▶ circle + square × triangle
=> 4 + 3 × 2
=> 4 + 6
=> 10

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Hope my ans.'s satisfactory.☺

Answer 2

Hi friend, Harish here.

Here is your answer:

1)  Let the value of square be x,

  x × x × x = x³ = 27 ,

 ⇒ x = ∛27 = 3

2) Let value of Triangle be y,

Then,
 
$3\times y\times y\times y = 24$

⇒ $y^{3} = \frac{24}{3} = 8$

⇒ $y = \sqrt[3]{8} = 2$

3) Let the value  of  circle  be ' z ' .

Then,

$3\times 2\times z\times z=96$

$z^{2} = \frac{96}{3\times 2}= \frac{96}{6} =16$

$z = \sqrt{16} = 4$

Therefore the final value is,

⇒  $4+ (3\times 2) = 4 + 6 = 10$
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Hope my answer is helpful to you.