Question

can you solve this question step by step

Answer 1

let the first radius=R
again,let the radius of second circle is =r

a.t.q

2πR-2πr=0.88

2π(R-r)=0.88

R-r=o.88×7/44

R-r = 88×7/44×100

R-r =0.14

again,a.t.q

R+r=5.6

using elimination method , after this you get the value of R and r

Answer 2

Let the radius of two circles be r and R respectively

Sum of diameter of two circles = 2.8 m

So, 2r + 2R =2.8
or, R +r =1.4

Difference in circumference = 2pi ( R-r) = 0.88
So, R - r = 0.88 × 7 /(22×2) =0.14 __(pi = 22/7)__

So adding both we get, 2R =1.54 m
or, R =0.77 m
So r = 1.4 - 0.77 = 0.63 m

Hope this is ur required answer.