Math, asked by krishu1284, 1 year ago

can you solve this trigonometric question

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Answered by Anonymous
1

Answer:


Step-by-step explanation:

1+sinФ/cosФ+cosФ/1+sinФ=2secФ

LHS=1+sinФ/cosФ+cosФ/1+sinФ

     =[1+sinФ]²+cos²Ф/cosФ[1+sinФ]

      =1+2sinФ+sin²Ф+cos²Ф/cosФ[1+sinФ]

      =1+1+2sinФ/cosФ[1+sinФ]                      ..............[as sin²Ф+cos²Ф=1]

      =2+2sinФ/cosФ[1+sinФ]

      =2[1+sinФ]/cosФ[1+sinФ]

       =2/cosФ

       =2secФ

If This helps you pls mark as a brainleast one

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