can you solve this trigonometric question
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Step-by-step explanation:
1+sinФ/cosФ+cosФ/1+sinФ=2secФ
LHS=1+sinФ/cosФ+cosФ/1+sinФ
=[1+sinФ]²+cos²Ф/cosФ[1+sinФ]
=1+2sinФ+sin²Ф+cos²Ф/cosФ[1+sinФ]
=1+1+2sinФ/cosФ[1+sinФ] ..............[as sin²Ф+cos²Ф=1]
=2+2sinФ/cosФ[1+sinФ]
=2[1+sinФ]/cosФ[1+sinФ]
=2/cosФ
=2secФ
If This helps you pls mark as a brainleast one
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