Math, asked by rajendrimandal51, 1 year ago

can you tell me answer please​

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Answered by Darkblaze123
0

HEY YOUR ANSWER IS HERE

TOTAL LENGTH OF ROPE = 11m

LENGTH OF TWO PEACES 12/5 AND 33/10m

SUM OF TWO PEACES = 12/5 + 33/10

= 57/10m

REMAINING ROPE = TOTAL LENGTH - THE SUM OF TWO LENGTHS PEACES

= 11 - 57/10

= 67/10m

SO THIS IS YOUR COMPLETE ANSWER WITH EXPLAINATION

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Answered by Anonymous
0

Answer:

Step-by-step explanation:

Length of I piece =2,2/5=12/5 meter

Length of II peice=3,3/10=33/10  meter

total length of I and II peiece

=12/5+33/10

=24/10+33/10=(24+22)/10=46/10

Hence length of the remaining part of rope

=11-46/10

=110/10-46/10

=(110-46)/10

=64/10 m

=6,4/10=6,2/5 meter

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