Question

can you tell me both​

Answer 1

$\boxed{\bold{\sf{Sum \ of \ two \ complementary \ angles = 90^o}}}$

1.

Given angles:

• (2x-7)°

• (x+4)°

Gives,

$\sf {\implies (2x - 7) + (x + 4) = 90}$

$\sf {\implies 2x - 7 + x + 4 = 90}$

$\sf {\implies 3x - 3 = 90}$

$\sf {\implies 3x = 90+3}$

$\sf {\implies 3x = 93}$

$\sf {\implies x = \dfrac{93}{3}}$

$\sf {\implies x = 31^o}$

$\boxed{\bold{\sf {Value \ of \ x = 31^o}}}$

2.

Given angles:

• (3x+15)°

• (2x+5)°

Gives,

$\sf {\implies (3x + 15) + (2x + 5) = 90}$

$\sf {\implies 3x + 15 + 2x + 5 = 90}$

$\sf {\implies 5x + 20 = 90}$

$\sf {\implies 5x = 90-20}$

$\sf {\implies 5x = 70}$

$\sf {\implies x = \dfrac{70}{5}}$

$\sf {\implies x = 14^o}$

$\boxed{\bold{\sf {Value \ of \ x = 14^o}}}$

Answer 2

Answer:

Complementary angles of the angles whose sum is equal to 90 degree

Let the measure of the angle be 2x and 3x

So 2X + 3 x is equal to 90

5x=90

X=90÷5

X=18

So angles are.

2×x=2×18=36°

3×x=3×18=54°

So the measure of the larger angle is 54 degree

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Step-by-step explanation:

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