Question

can you use this method determining refractive index of a highly volatile liquid? Explain​

Answer 1

Explanation of the method of determining refractive index of a highly volatile liquid is as follows:

• On the phenomenon of refraction, refractometer's principle is based.
• Through the surface of the liquid, light passing generates reflection. According to the law of reflection, after that the refractive index is measured.
• 4.05 is the highest refractive index for the element Germanium. It happens under natural conditions.
• In a visible region, it drops to lower values.

Answer 2

Refractive Index is Ratio of Speed of Light & its Phase Velocity

Explanation:

Determination of Refractive Index by use of Convex Lens

Refractive Index is Dimensionless Number

It elaborates the Propagation of Light in a  Medium

And defined as:

                                                       $n = \frac {c}{v}$

where c = speed of light in vacuum  

v = phase velocity of light  

It also measures the amount of light bent or  is refracted while medium entry.

There is a change in direction from one to another medium, in case of light.

Let us suppose,

• i = Angle of incidence for ray (vacuum)

• r = Angle of refraction

So, we can define the refractive index as 'n' is defined as  

$n = \frac {sin i}{sin r}$

• When a convex lens is placed over some drops of the given liquid on a plane mirror, a plano-concave liquid lens is formed between the lens and the mirror.

• If $f_1$ is the focal length of the convex lens and F is the focal length of the combination of a convex lens and plano-concave liquid lens, the focal length of the liquid lens $f_2$ is given by,

$f_2 = \frac {Ff_1}{f_1 - F}$

If R is the radius curvature of the face of the convex lens which is in contact with the liquid, then the refractive index of the liquid is,

$n_l = 1+ \frac {R}{f_2}$