Can you write a linear equation in the slope-intercept form using the points (3,4) and (5,8)? Explain
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(y2-y1)/(x2-x1) =y-y1/x-x1
(8-4)/(5-3)= y-4/x-3
1=(y-4)/(x-3)
x-3=y-4
y= x+1
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