Candidate of our school appear in a mathematics test. The data were as follows:
Schools:
I
II
III
IV
No.of candidates
60
48
not available
40
Average Score
75
80
55
50
If the average score of the candidates of all the four schools is 66, find the number of candidates that appeared from school III
Answers
Answered by
44
ARITHMETIC MEAN OR MEAN OR AVERAGE :
The arithmetic mean of a set of observations is obtained by dividing the sum of the values of all observations by the total number of observations .
Mean = Sum of all the observations / Total number of observations .
MEAN = Σfixi / Σfi
[‘Σ’ Sigma means ‘summation’ ]
FREQUENCY DISTRIBUTION TABLE IS IN THE ATTACHMENT
Let the number of candidate that appeared from school III be x .
From the table : Σfixi = 10340 + 55x , Σfi = 260
MEAN = Σfixi / Σfi
Given : Average score (Mean) = 66
66 = 10340 + 55x/ 260
66 × 260 = 10340 + 55x
17160 = 10340 + 55x
55x = 17160 - 10340
55x = 6820
x = 6820/55 = 124
x = 124
Hence,the number of candidate that appeared from school III is 124 .
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Answered by
65
Let Number of. candidates appeared
from school III = p
Mean = Σfixi/Σfi = 66 [ Given ]
=> ( 10340 + 55p )/( 148 + p ) = 66
=> 10340 + 55p= 66( 148 + p )
=> 10340 + 55p = 9768 + 66p
=> 10340 - 9768 = 66x - 55p
=> 572 = 11p
=> ( 572/11 ) = p
=> 52 = p
p = 52
Therefore ,
Number of candidates that appeared
from school III = p = 52
••••
from school III = p
Mean = Σfixi/Σfi = 66 [ Given ]
=> ( 10340 + 55p )/( 148 + p ) = 66
=> 10340 + 55p= 66( 148 + p )
=> 10340 + 55p = 9768 + 66p
=> 10340 - 9768 = 66x - 55p
=> 572 = 11p
=> ( 572/11 ) = p
=> 52 = p
p = 52
Therefore ,
Number of candidates that appeared
from school III = p = 52
••••
Attachments:
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