Question

candidate who is course 30% fails by 5 marks while another candidate who scores 40% marks gets 10 more than minimum pass mark what are the minimum pass marks required to pass​

Answer 1

Answer:

This Can be solved algebraically as follows…

Step-by-step explanation:

A candidate who scores 30% fails by 5 marks while the other scores 40% and gets 10 more than minimum pass marks. What are the minimum marks required to pass?

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This Can be solved algebraically as follows…

We assume total marks = x

1st Candidate scores 30% of x = 3x/10

Fails by 5 marks

So, minimum pass marks=( 3x/10) + 5

= (3x + 50) /10 …………(1)

2nd candidate scores 40% of x = 4x/10

He svores 10 more than minimum

=> minimum pass marks = (4x/10) - 10

= (4x-100) / 10 …………. (2)

(1)&(2) are eaqual

=> (3x+ 50)/10 = (4x- 100) / 10

=> 3x + 50 = 4x - 100

=> x = 150

=> minimum pass marks by (1)

=( 3x+50)/10

= (3 x 150 + 50) /10

=> 500/10

= 50 marks out of 150 is required to pass

So minimum pass percentage =

(50/ 150) x 100

= 100/3

= 33.3 %