Question

cant get the answer please help​

Answer 1

Here it is.... Please post such questions... Its helps me tooo

Answer 2

(x/a)cosQ+(y/b)sinQ=1

(x/a)sinQ -(y/b)cosQ=1

now by elimination method.

CosQ((x/a)cosQ + (y/b)sinQ=1)

sinQ((x/a)sinQ - (y/b)cosQ =1)

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x/a(sinQ²+ cosQ²)=cosQ+sinQ

( 1. )

x/a=cosQ+sinQ

now put in any one eqn you will get:

"y/b=sinQ-cosQ"

acc.to question

x²/a²+y²/b²=2

so,

(sinQ+cosQ)²+(sinQ-cosQ)²

(SinQ²+cosQ²+2sinQ. cosQ + sinQ²+cosQ² - 2sinQ.cosQ . )

(sinQ²+cosQ²=1)

1+1

=2

hope it will help you

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