CaO + CO2 gives CaCO3
why is this not an example of standard molar enthalpy of formation?
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Explanation:
Given:
CaCO3(s)→CaO(s)+CO2(g),ΔH=42KJ
ΔH=ΔHf(CO2)+ΔHf(CaO)−ΔHf(CaCO3)
42=−94+(−152)−ΔHf(CaCO3)
42=−246−ΔHf(CaCO3)
=ΔHf(CaCO3)
−288KJ
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