Capacitance C1 = 2C2 = 2C3 and potential
difference across C1, C2and C3 are V1,V2 and
V3respectively then :
(1) V1 = V2 = V3
(2) V1 = 2V2 = 2V3
(3) 2V1 = V2 = V3
(4) 2V1 = 2V2= V3
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Answer:
Energy stored in a capacitor = 1/2QV = 1/2CV^2 = 1/2(Q^2/C)
Now, in a series connection, the Q across each capacitor is same.
And 1/Ceq = 1/C1 + 1/C2 + 1/C3
Hence, energy in series connection = Q^2/2 * ( 1/C1 + 1/C2 + 1/C3)
Also, since,for any capacitor V= Q/C, so in this circuit Q/C1 + Q/C2 + Q/C3 = V
Hence, energy in series connection becomes = Q/2 * V
Hence, energy in series connection becomes = Q/2 * V
Now in parallel connection, V across each capacitor is same.
And Ceq = C1+ C2+C3
Hence energy stored in parallel connection = 1/2*V^2 ( C1+ C2+C3)
Also, since,for any capacitor V= Q/C, so in this circuit C1V + C2V + C3V = Q
Hence, energy in series connection becomes = 1/2QV
Hence, energy in series and parallel connection is same.
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