Question

capacitance of a capacitor by a thin metal foil is 2 . if the foil is folded into itself with a paper of thickness 0.15 mm and dielectric constant of paper is 205 , width of paper is 40mm then length of foil will be
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Answer 1

The length of the foil is 33.91 m

Explanation:

Here, let the length be "l"

Width is "b" = 400 mm= 0.4 m

Thickness, t=  0.15 mm = 15 × 10^−5  m

As capacitance for parallel plate capacitor is,  

C = Kϵo A/d = Kϵo (l×b)/t

l = Ct / Kϵob = 2 × 10^ −6  × 15 × 10^−5 / (2.5 × 8.85 × 10^−12  × 0.4)

  = 33.91 m

Thus the length of the foil is 33.91 m

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