Question

Capacitance of a parallel plate capacitor, having parallel plates of area 6cm square placed at a separation of 2mm

Answer 1

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capacitance of parallel plate capacitor

C = epsilon nod x A / d



C = 8.85*10^-11 x 6*10^-2 / 2*10^-3

C= 26.5*10^-10F

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