capacitance of parallel plate capacitor when there is no medium between the plates is C0 if capacitor is now completely filled with dielectric matter of constant K the capacitance
(a) C0/K
(b) KC0
(c) K^2C0
(d) 2KC0
Answers
Answer: The answer to this question is-
capacitance of parallel plate capacitor when there is no medium between the plates is if capacitor is now completely filled with dielectric matter of constant K then the capacitance is .
Explanation:
The quantity of charge that a parallel plate capacitor can store depends on its capacitance. If you look at the equation above, you can see that the more C is worth, the more charge a capacitor can store. As a result, it is clear that the capacitance depends on:
- the separation of two plates, d between the plates, in the medium's area A.
- The electric field can be expressed in writing using the Gauss law as follows:
E = Q/εA ⇒ Ed = V = Qd/εA
We can write capacitance as follows since we are aware that it is defined by the formula V = Q/C:
C = εA/d
We achieve the highest capacitance when the plates are arranged closely together and have a big surface area.
The material's tiny dipole moment will protect the charges on the two plates. As a result, it will change how the dielectric material between the two plates behaves. Materials have a relative permeability, or k, which determines their permeability. Thus, the capacitance is:
C= εA/d = KεA/d
By adding a dielectric between the plates of a parallel plate capacitor, we can enhance its capacitance because the dielectric has permeability k larger than 1. K is occasionally referred to as the dielectric constant.
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