Question

capacitor C1(10uF)and C2(20uF) are connected in a series across a 3kV supply as shown.What is the charge on capacitor C1?????​

Answer 1

Answer:2×10^-2C

Explanation:

Answer 2

Answer:

The charge on capacitor C1 is 20kC.

Explanation:

Let's start by determining the circuit's equivalent capacitance.

$\frac{1}{C_{eqv}} =\frac{1}{C_1} +\frac{1}{C_2}$

$\frac{1}{C_{eqv}} =\frac{1}{10} +\frac{1}{20}$

$\frac{1}{C_{eqv}} =\frac{2+1}{20}$

$C_{eqv}=\frac{20}{3}\mu F$   (1)

We know that when the capacitors are connected in series the charge through them remains the same. The charge on the capacitors is calculated as,

$Q=C_{eqv}V$     (2)

By inserting the required entities  in equation (2) we get;

$Q=\frac{20}{3}\times 10^{-6}\times 3\times 10^3$

$Q=20\times 10^3$

$Q=20\ kC$

The charge on capacitor C1 is 20kC.

#SPJ3