Capacitor is to have an energy content of 20J it must be placed across potential difference of?
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The voltage required on a capacitor for it to store a particular amount of energy depends on the capacitance of the capacitor. The energy stored on a capacitor is:
Energy = (1/2) × C × V².
Solving for V gives: V = square root( 2 × Energy/C).
So, if a capacitor of 1 Farad stores 20 Joules, then it presents a voltage of:
V = square root(2 × 20/1) = square root of 40 = 6.325 volts.
A one microfarad capacitor must be charged to 6325 volts to store that same amount of energy.
Hope it helps!
Brainliest please! :)
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