Question

Capacitor is to have an energy content of 20J it must be placed across potential difference of?

Answer 1

Answer

"Capacitor" here means  the question states its value 1Farad.

Energy stored = 0.5 $CV^{2}$

20 = 1* $V^{2}$

V= $\sqrt[]{20}$ ~ =4.47 Volts (approx)