Question

Capacitor of capacitance 2 µF and 4µF are connected in series. Potential difference of 120 volt is applied across the combination. The potential difference across the capacitor of2 µF is...​

Answer 1

Answer:

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Answer 2

Total capacitance equivalent = 2 × 4/ (2 + 4) = 8/6 = 4/3

Q = CV

Q = 120 x 4/3

Q= 160

V = q/V

V =160/2

V = 80

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