Question

Capacitor of capacitance 50uf is charged to a potential of 1000V. calculate the energy stored in the capacitor

Answer 1

Capacitance C = 50 uF = 50 × 10^-6 F
Potential Difference , V = 1000 V
The energy stored in the capacitor E = C × V × V /2 = 50 × 10 ^-6 × 1000 × 1000 /2
= 50 / 2
= 25 J

Answer 2

Answer:

A capacitor of capacitance 50uf is charged to a potential of 1000V. The energy stored in the capacitor will be $25\ J$

Explanation:

• Let us consider a capacitor of capacitance C and with a potential difference between the capacitor plates V.

• Electric potential energy (E) stored in the capacitor  can be expressed as,

            $E=\frac{1}{2} C V^{2}$    ...(1)

In the question, it is given that,

$V= 1000\ V$

$C =50\ \mu F = 50\times10^{-6} F$

Substitute these  values into equation (1)

$E=\frac{1}{2}\times 50\times10^{-6} \times 1000^{2} = 25 \ J$

Thus,

The energy stored between the plates of capacitor  will be   $25\ J$