CAPACITORS
3.
OBJECTIVE
In the circuit, all capacitors are identical, each of capacity 2uF and they are infinite in
is connected to a battery of 10V, then the charge drawn from the battery is :
1) 40uc
2) 20uc
HHHH
H8 capacitors
H 16 capacitorsH
3) 10uc
4) 51C
B
Answers
Answer:
Explanation:
Characteristics of the image form by the plane mirror are:
Since the image form by the plane mirror has magnification is 1 then,
(I). The size of the image form will be the same as the size of the object.
(II). The distance of the image from the mirror will be the same as the distance of the object from the mirror.
(III). The image form will be virtual.
(IV). The image form will be upright.
the position of image related to the position of the object
The image is as far behind the mirror as the object is in front of it i.e, the perpendicular distance of image from the mirror is equal to the perpendicular distance of object from the mirror.
Complete question:
In the circuit, all capacitors are identical, each of capacity 2μF and they are infinite in number. If AB is connected to a battery of 10V then the charge drawn from the battery is:
Answer:
The charge drawn from the battery is 40 μF.
Explanation:
Let us consider the resultant of capacitors in the first column as C1, and that of the 2nd column as C2, and so on.
And given that the terminals AB are connected to a battery of 10V.
Now, the capacitances:
C1 = 2μF.
C2 = (2 × 2)/(2 + 2) = 1 (As they are 2 capacitors and are connected in series)
C3 = 2/4 = 1/2 (As they are 4 capacitors and are connected in series)
C4 = 2/8 = 1/4 (As they are 8 capacitors and are connected in series)
.
.
Now the capacitors C1, C2, C3... are connected in parallel, so the effective capacitance (C) is:
C1 + C2 + C3 + C4 + C5 .... = C
2 + 1 + (1/2) + (1/4) + (1/8) + .... = C
We can clearly see that the series is infinite GP.
So,
C = 4 μF.
But we know that Q = CV
⇒ Q = 4μF × 10V
⇒ Q = 40 μC.
Therefore, the charge drawn from the battery is 40 μF.
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