Physics, asked by uyo4854, 1 month ago

capacitors are combined in which arrangement when we require large capacitance at small potentials ?​

Answers

Answered by Anonymous
6

Capacitors

CapacitorsThe potential V of a conductor depends upon the charge Q given to it. According to observations, the potential of a conductor is proportional to the charge on it.

CapacitorsThe potential V of a conductor depends upon the charge Q given to it. According to observations, the potential of a conductor is proportional to the charge on it.Q ∝V or Q = CV

CapacitorsThe potential V of a conductor depends upon the charge Q given to it. According to observations, the potential of a conductor is proportional to the charge on it.Q ∝V or Q = CVThe proportionality constant ‘C’ is known as the capacitance of the conductor. Thus,

CapacitorsThe potential V of a conductor depends upon the charge Q given to it. According to observations, the potential of a conductor is proportional to the charge on it.Q ∝V or Q = CVThe proportionality constant ‘C’ is known as the capacitance of the conductor. Thus,C = Q/V

CapacitorsThe potential V of a conductor depends upon the charge Q given to it. According to observations, the potential of a conductor is proportional to the charge on it.Q ∝V or Q = CVThe proportionality constant ‘C’ is known as the capacitance of the conductor. Thus,C = Q/VThe capacity of a conductor is the ratio between the charge of the conductor to its potential. If V = 1, then C = Q. The capacity of a conductor is the charge required to raise it through a unit potential.

Answered by steffis
6

To increase the capacitance at small potential we need to arrange and connect capacitors in parallel.

Explanation:

C= ε \frac{A}{d}

As we know, Capacitance depends upon ε , A and d. We can increase capacitance by :

ε : increasing relative permitivity.

d : decreasing separation between the plates.

A : increasing cross sectional area of plate.

This is a hard process so to make this process easy we make the arrangements of capacitors in parallel so that we can increase capacitance.

When two capacitors are connected parallel then ,

C=C_{1}+C_{2}

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