Question

Capacity of tap B is 80% more than
that of A. If both the taps are opened
simultaneously, then take 45 hours to fill
the tank. How long will B take to fill the
tank alone?​

Answer 1

Answer:

70 hour

Step-by-step explanation:

let time taken by B to fill the tank be x hour

therefore, time taken by A to fill the tank

b=x+(x × 80/100)

=9x/5 hour

according to the formula,

time taken by both taps to fill the tank

time=ab/a+b

45=[(x×9x/5) / (x+9x/5)]

45×14x/5=9x²/5

.°. x=45×14/9

=70 Ans.....

hope this will help you