Question

Capculate the number of atoms in 0.5 mole molecules of nitrogen

Answer 1

Numberof atoms = No. of moles * Avagadro's constant
Now, Avagadro's constant = 6.022 * 10^23
No. of atoms = 0.5 * 6.022 * 10^23 = 3.011 * 10^23 atoms

Answer 2

In 1 mol of any substance there are 6.033 *1023 atoms
so In 1/2 mole of nitrogen
6.022*10^23/2 atoms
3.011 *10^23 atoms