Question

Capillary rise of water in a tube of diameter 0.2 mm. Take surface tension of water as 0.07 N/m, specific weight of water as 9810 N/m3 and contact angle is 0 degree
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Answer 1

Answer:

Explanation:

We have,

       h=2Tcosθ/ρrg

Given,

      Specific weight=9810 N/m3

Therefore density of water= Specific weight/9.81

                                           =1001kg/m3

Substituting in the equation,

            h=(2*0.07*cos0)/(1001*0.1*10^-3*9.8)

              =14.2cm