Math, asked by suzukililly396, 7 months ago

Captain Daniel has a ship, the H.M.S Crimson Lynx. The ship is two furlongs from the dread pirate Stephanie and her merciless band of thieves.
If his ship hasn't already been hit, Captain Daniel has probability 3/4 of hitting the pirate ship. If his ship has been hit, Captain Daniel will always miss.

If her ship hasn't already been hit, dread pirate Stephanie has probability 1/7 of hitting the Captain's ship. If her ship has been hit, dread pirate Stephanie will always miss.

If the Captain and the pirate each shoot once, and the pirate shoots first, what is the probability that both the pirate and the Captain hit each other's ships?

Answers

Answered by abhishek12348930
3

Answer:

42 is it I think so

Step-by-step explanation:

i am not in maths but just helping u out

Answered by tomsfy
0

Answer:

0

Step-by-step explanation:

The answer below is given by khan academy.

If the pirate hit the Captain's ship, the Captain has no chance of firing back. So, the probability of the Captain hitting the pirate ship given the pirate hitting the Captain's ship is 0. The probability that both the pirate and the Captain hit each other's ships is then the probability of the pirate hitting the Captain's ship times the probability of the Captain hitting the pirate ship given the pirate hitting the Captain's ship.

This is 1/7 * 0 = 0

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