Math, asked by Shobhit6481, 2 months ago

Captain Michael has a ship, the H.M.S. Khan. The ship is two furlongs from the dread pirate William and his merciless band of thieves.
The Captain has probability \dfrac{2}{3}
3
2

start fraction, 2, divided by, 3, end fraction of hitting the pirate ship. The pirate only has one good eye, so he hits the Captain's ship with probability \dfrac{1}{3}
3
1

start fraction, 1, divided by, 3, end fraction.

Answers

Answered by amitnrw
1

Given  : Captain Michael has a ship, the H.M.S. Khan.

The Captain has probability 2/3  to hit

The pirate only has one good eye, so he hits the Captain's ship with probability 1/3 .

Any one can hit if its not already hitted.

Captain and the pirate each shoot once, and captain shoot first

To Find :   Probability that pirate hit  the H.M.S. Khan.

Solution:

Probability that pirate hit  the H.M.S. Khan.

Pirate can only hit if  captain misses

Probability that captain misses  = 1- Probability captain hit

1  - 2/3  =  1/3

Probability pirate hit  = 1/3

Probability pirate hit  =  captain misses  * pirate hit

(1/3) (1/3)  = 1/9

if both hit together then probability that bot hit each other

= (2/3) (1/3)

= 2/9

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