Math, asked by forjojostreamschat, 9 months ago

Captain Nadia has a ship, the H.M.S Crimson Lynx. The ship is two furlongs from the dread pirate Tiffany and her merciless band of thieves.
If her ship hasn't already been hit, Captain Nadia has probability \dfrac{1}{2}
2
1

start fraction, 1, divided by, 2, end fraction of hitting the pirate ship. If her ship has been hit, Captain Nadia will always miss.
If her ship hasn't already been hit, dread pirate Tiffany has probability \dfrac{2}{7}
7
2

start fraction, 2, divided by, 7, end fraction of hitting the Captain's ship. If her ship has been hit, dread pirate Tiffany will always miss.
If the Captain and the pirate each shoot once, and the Captain shoots first, what is the probability that the Captain misses the pirate ship, but the pirate hits?

Answers

Answered by amitnrw
1

Given :Captain Nadia has a ship, the H.M.S Crimson Lynx. The ship is two furlongs from the dread pirate Tiffany and her merciless band of thieves.

Captain shoots first,

To Find : what is the probability that the Captain misses the pirate ship, but the pirate hits

Solution:

If ship has not been hit

Captain Nadia has probability   of hitting the pirate ship  = 1/2

=> Captain Nadia has probability   of not hitting the pirate ship  =1 - 1/2 = 1/2

If ship has   been hit

Captain Nadia always miss

If ship hasn't already been hit,

dread pirate  has probability   of hitting the captain ship = 2/7

dread pirate  has probability   of not hitting the captain ship = 1-2/7 = 5/7

If ship has   been hit

dread pirate always miss

Captain misses the pirate ship, but the pirate hits  

Captain misses the pirate ship = 1/2

pirate hits   = 2/7

Probability that  Captain misses the pirate ship, but the pirate hits   = (1/2)(2/7) = 1/7

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