Car 1 is traveling at a speed of 6 m/s (meters per second) with an acceleration of 3 m/s^2 (meter per second squared). Car 2 is traveling at a speed of 4 m/s and is accelerating at a rate of 8 m/s^2. Which car is travelling the fastest at that point in time? Why?
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Answer:
CAR 1 is faster
Explanation:
v= final speed, u= initial speed
Accelaration= v-u/t
Accelaration/ v-u = t
CAR 1
Speed= 6m/s
Accelaration=3m/s²
3/ 6(v)-0(u)= t
3/6=t
0.5 secs is the time taken by CAR 1
CAR 2
Speed= 4m/s
Accelaration=8m/s²
8/ 4(v)-0(u)= t
8/4=t
2 secs is the time taken by CAR 2
CAR 1 time taken= 0.5 sec
CAR 2 time taken = 2 sec
Therefore CAR 1 IS faster than CAR 2
Hope it helps
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