Question

Car A and car B start moving simultaneously in the same
direction along the line joining them. Car A moves with a constant acceleration
a = 4 m/s", while car B moves with a constant velocity v = 1 m/s. At time = 0,
car A is 10 m behind car B. Find the time when car A overtakes car B.​

Answer 1

Acceleration,a=4m/s

2

,velocity,v=1m/s,t=0,d=10m

So, By the formula:

s=ut+

2

1

at

2

0=−t+

2

1

×4×t

2

=2t

2

−t−10=0

=2t

2

+4t−5t−10=044

=2t(t+2)−5(t+2)

(2t−5)(t+2)

=2t−5=0

t=2.5s

Since Time never be in negative.

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