Question

Car A moves behind Car B at a distance of 1000m with car B moving at constant speed
of 10m/s. At what speed must car A be moving if it overtakes car B in 100 seconds.​

Answer 1

Distance traveled by car A=Sᵃ

Distance traveled by car B=Sᵇ

According to formula S=ut+½at²

Sᵃ=0t+½×2t²

Sᵇ=10t+½×0t²

Car A will overtake car B when

Sᵃ=Sᵇ+100

Putting the value Sᵃ and Sᵇ

+2=10t+100

+2−10t−100=0

After solving for t, we get

t=16.18sec possible

t=−6.10sec not possible

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