Question

Car A moving along a straight horizontal road with a
velocity 60 kmh-l is followed by car B moving with a
velocity 70 km.h-1. When car B is at a distance 2.5
km from car A, car B applies a retardation of
20 km · h-2. Where and when will the two cars meet?
[32.5 km, h)​

Answer 1

Answer:

For B to catch A both will have to reach the same point in same time.

Let that distance be x . B will have to cover x+2kmin the same time.

For B equation will be

x=60km/hr×t

t=

60

x

hr

For A equation will be

x+2=70km/hr×

60

x

hr+

2

1

×−20km/hr

2

×(

60

x

)

2

x

2

−60x+720=0

The solution for the above equation using the quadratic formula will be

x=30(1±

2

)km

As we have to find the shortest distance, that distance will be

x=30(1−

2

)km

Explanation:

hope it help uuu...