Question

Car A, moving at a constant speed of 30m/s, passes a stationary car, B. Immediately after this, car B starts from rest and accelerates uniformly at 2m/s² until it reaches a speed of 40m/s. It then continues forward, maintaining this speed. Find the time taken by car B to overtake car A and the distance from the starting point when the overtaking occurs.

Answer 1

Answer:

v=40 m/s

u= 0 m/s

a= 2 m/s²

t=?

Using Kinematical Equation,

v=u+at

40= 0+ (2×t)

40= 2t

t= 40/2

= 20 seconds

Answer 2

Answer:

20 second

Step-by-step explanation:

v=at

40=0+(2×t)

40=2t

t=40/2

t=20

that's why 20 second