Physics, asked by greshagresha7348, 10 hours ago

Car 'a' travel a distance of 180km in 4hours while a car'b' cover a distance of 240km in 6 hours . which car is moving faster?​

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Answers

Answered by yash276343
6

Explanation:

speed=distance/time

speed of car A=180/4=45km/hr

speed of car B=240/6=40km/hr

car A is moving faster than car B

Answered by Anonymous
53

Given :

  • ➙ Car A travels a distance of 180 km in 4 hrs.
  • ➙ Car B travels a distance 240 km in 6 hrs.

 \\ {\underline{\rule{200pt}{3pt}}}

To Find :

  • ➙ Which car is moving faster .

 \\ {\underline{\rule{200pt}{3pt}}}

Solution :

~ Formula Used :

\large{\orange{\bigstar}} \: \: {\underline{\boxed{\red{\sf{ Speed = \dfrac{Distance}{Time}}}}}}

 \qquad{\rule{150pt}{1pt}}

~ Calculating Speed in condition of Car A :

{\longmapsto{\qquad{\sf{ Speed{\small_{(Car \: A )}} = \dfrac{Distance}{Time}}}}} \\ \\ \ {\longmapsto{\qquad{\sf{ Speed{\small_{(Car \: A )}} = \dfrac{180}{4}}}}} \\ \\ \ {\longmapsto{\qquad{\sf{ Speed{\small_{(Car \: A )}} = \cancel\dfrac{180}{4}}}}} \\ \\ \ {\qquad{\textsf{ Speed of Car A = {\color{blue}{\sf{ 45 \: Km/h }}}}}}

 \qquad{\rule{150pt}{1pt}}

~ Calculating Speed in condition of Car B :

{\longmapsto{\qquad{\sf{ Speed{\small_{(Car \: B )}} = \dfrac{Distance}{Time}}}}} \\ \\ \ {\longmapsto{\qquad{\sf{ Speed{\small_{(Car \: B )}} = \dfrac{240}{6}}}}} \\ \\ \ {\longmapsto{\qquad{\sf{ Speed{\small_{(Car \: B )}} = \cancel\dfrac{240}{6}}}}} \\ \\ \ {\qquad{\textsf{ Speed of Car B = {\pink{\sf{ 40 \: Km/h }}}}}}

 \qquad{\rule{150pt}{1pt}}

~ Calculating the Greater Speed :

\qquad{\sf{ Speed{\small_{(Car \: A )}} = 45 \: km/h }}

 \\ \qquad{\sf{ Speed{\small_{(Car \: B )}} = 40 \: km/h }}

 \\ \\ {\underline{\boxed{\purple{\sf{ Car \: A \: is \: travelling \: faster .}}}}}

 \qquad{\rule{150pt}{1pt}}

Therefore :

Car A is traveling at faster speed .❞

 \\ {\underline{\color{darkblue}{\rule{300pt}{9pt}}}}

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