Question

А

car accelerates, uniformly from 10 km/h to
20km/h in 6 seconds, calculate the
acceleration and distance covered by car in
that time.​

Answer 1

Answer:

0.46,24.48

Step-by-step explanation:

t=6s

First convert, km/hr ---- m/s by multiplying 5/18

u= 10x5/18 ==  2.77

v= 20x5/18 == 5.55

accelaration= (v-u)/t

= (5.5-2.7)/6

=2.8/6

=0.46

distance=

S= ut + at^2/2

S= 2.7x6 + 0.46x6x6/2

=16.2+ (16.56/2)

=16.2+ 8.28

=24.48