Question

car accelerates uniformly from 18 km per hour to 36 km per hour in 5 seconds calculate the acceleration and the distance covered by the car

Answer 1

Here,
initial velocity(u)= 18km/h or 18×5/18m/s= 5 m/s
final velocity (v)= 36km/h or 36×5/18m/s= 10m/s
Time (t)= 5 seconds
Acceleration= v-u/t
a= 10-5/5 = 5/5= 1m/s²

Now,
v²-u²= 2as
v²-u²/2a= s
(10)²-(5)²/2×1= s
100-25/2= 75/2= 37.5 m = distance travelled

Answer 2

Acceleration = Change in Velocity/Time
Change in Velocity = 36-18 = 18 km/h=5 m/s
Time= 5 Seconds
Acceleration = 5/5= 1 m/s2

Equation of motion,s=ut+(1/2)at2
u=18 km/h=5 m/s
t=5 s
a=1 m/s2
s= (5*5)+(1/2*1*5*5)
s=25+12.5 i.e., s=37.5 m
Hope you are clear with my explanations