Question

car accelerates uniformly from 18km/h to 36km/h in 5s. Calculate:
1 the acceleration.
2) the distance covered by the car
​

Answer 1

Explanation:

1)a=36-18/5=18/5=3.5km/h

2)distance=speed×time=18×5=90m

Answer 2

Answer:

(1): 1 m/s²

(2): 37.5 m

Explanation:

18 km/hr = (18*5/18) m/s = 5 m/s

36 km/hr = (36*5/18) m/s = 10 m/s

Initial velocity = u = 5 m/s

Final velocity = v = 10 m/s

Time taken = t = 5 s

Using equations of motion:

= > v = u + at

= > 10 = 5 + a(5)

= > 10 - 5 = 5a

= > 1 m/s² = a { answer 1 }

= > v² = u² + 2aS

= > 10² = 5² + 2(1)S

= > 100 - 25 = 2S

= > 75/2 = S

= > 37.5 m = S